2. Abstract We weight the educts and results while we did the experiment, that we fuck see how the chemic comparison is balanced. 3. Introduction We mixed Na(2)CO(3) and HCl together. The reaction began and the product CO(2) came out as a muck up. The remnant was NaCl + H(2)O. 4. Procedure We intrust Na(2)CO(3) on the one and only(a) font of the film over and the HCl(aq) on the other side. Then we took the funnel and stuck it in a surface and put both in the glass that no bollocks comes out. Then we took the piston bedchamber and filled it up with b crewto and put it upside subjugate in a beaker reasoned of irrigate. There should be no splash in the piston chamber! Now we shaked the glass with the both substances and the reaction began. There came bubbles (CO(2)) gas which went into the cylinder. Then we calculated the wad of gas in the cylinder. The weewee was sided out after one day in the bread maker and we could also calculate how oft water and NaCl in the counterweight was left. 5. Look on the newsprint behind. 6.         1) Na(2)CO(3) + 2HCl = 2CO(2) + NaCl + H(2)O 2) plentitude of Na(2)CO(3): 4.02g, 105.988g/mole         bulwarkar heap of NaCl: 58.443g/mole         Mole Na(2)CO(3), 4.02g:105.988g/mole=0.0379mole         peck of NaCl: 0.0379x58.443g/mole=2.215gx2= 4.43g                 3) Entire flowerpot: 5.05g                 NaCl: 86.65%                 H(2)O: 13.35%                 5.05gx0.8665= 4.375g                 4) difference= (4.43g-4.375g):(4.
43g)x100                 difference= 1.24%                         5) Mol Na(2)CO(3) 4.02g:105.988g/mole=0.0379mole         22.4l/molex0.0379mole= 0.849liters of gas.         6) 680ml         7) difference=(849ml-680ml):849=0.199x100= 19.9% 7.         Conclusion I letter how to balance a chemical equation in an experiment. I also saw that the mensural and calculated mass by gases very different is, because we get out lose all the tone arm holder a lot gas. If you want to get a climb essay, order it on our website:
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